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10x^2-x+5=3x
We move all terms to the left:
10x^2-x+5-(3x)=0
We add all the numbers together, and all the variables
10x^2-4x+5=0
a = 10; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·10·5
Δ = -184
Delta is less than zero, so there is no solution for the equation
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